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Limiting Factor Analysis and throughput accounting

CIMA Free Mock Exam

1 Introduction

A production plan is easy when nothing is short: make as much of everything as you can sell. It stops being easy the moment one resource runs out before demand does. Then the question changes. It is no longer “is this product profitable?” but “what is the best use of the resource we have not got enough of?” — and those two questions have different answers.

A limiting factor (or scarce resource, or key factor) is any resource that stops an organisation producing enough to meet demand in full: machine hours, labour hours, a raw material, floor space, a licence. This chapter deals with the case of one limiting factor. Where two or more resources are short at the same time the technique is linear programming, which is chapter 8.

The chapter takes the same short-term decision twice. First on the conventional marginal-costing assumption, where materials, labour and other variable costs all vary with output. Then on the throughput assumption, where in the short term the only variable cost is material. The two assumptions produce different rankings, different plans and different profits from identical data, which is the point of doing both.

Syllabus

This chapter serves P1C3c — product mix decisions with constraints, and the “product mix” topic under P1C1b. Chapter 8 completes it for two or more constraints, and chapter 14 covers the other short-term decisions (make or buy, discontinuation).

2 Identifying the limiting factor

Before ranking anything, prove that a resource really is short. Compare what full demand would need with what is available:

  • work out the maximum demand for each product;

  • multiply by the resource each unit uses, and total it;

  • compare that total with the quantity available.

If the requirement is less than or equal to what is available the resource is not a limiting factor at all, and the plan is simply to meet demand in full. If more than one resource fails this test, there is more than one limiting factor and the technique is linear programming (chapter 8).

Demand itself is a constraint in exactly the same sense, and it is easy to forget. There is never any point in making a unit that cannot be sold, so maximum demand caps every product, however profitable it looks.

3 Ranking by contribution per unit of the limiting factor

3.1 Why contribution, and not profit

In the short term the total fixed costs do not change with the production plan. Whatever mix is chosen, the same fixed costs are incurred. So the plan that earns the most contribution is the plan that earns the most profit, and the fixed cost per unit on the cost card is simply irrelevant to the choice.

That matters here because a cost card that absorbs fixed overhead can make two products look equally attractive when they are not. In example 1 below both products show a profit of $2 a unit and they are not equally attractive at all.

3.2 Why per unit of the limiting factor

Contribution per unit answers “which product is worth more?”. That is the wrong question when a resource is short, because the products do not consume the resource at the same rate. The right question is “which product is worth more per hour (or per kilogram) of the thing we have run out of?”

Take two hours of machine time in example 1. Two hours makes one unit of A and earns $5 of contribution; the same two hours makes two units of B and earns $8. B is the better use of the machine even though A earns more per unit.

Contribution per unit of limiting factor = Contribution per unit ÷ Units of the limiting factor per unit

3.3 The method

The rule

Rank the products by contribution per unit of the limiting factor — highest first — and work down the ranking, making as much of each product as can be sold, until the limiting factor runs out.

In full, the steps are:

  • calculate the contribution per unit of each product (selling price less all variable costs);

  • identify the limiting factor and the quantity of it each unit needs;

  • calculate the contribution per unit of the limiting factor for each product;

  • rank the products on that figure, highest first;

  • allocate the limiting factor down the ranking, capping each product at its maximum demand, until the resource is exhausted;

  • if the question asks for profit, total the contribution and deduct the total fixed costs.

3.4 Fixed costs when only a rate per unit is given

A question that asks for profit, and gives fixed costs only as an absorbed amount per unit, is asking you to make an assumption — state it.

The cost card was prepared before anyone knew the resource would be short, so the absorption rate was set on budgeted output, which was full demand. The total fixed cost is therefore the rate per unit multiplied by the maximum demand, not by the units actually produced — and because it is a fixed cost it stays at that total even though the plan produces fewer units.

Do not multiply the fixed cost per unit by the units in your production plan. That treats a fixed cost as if it varied with output, which contradicts the assumption the whole technique rests on. In example 1 that error understates fixed costs by $3,000 and overstates profit by the same amount.

This lecture teaches the conventional method through example 1 and is a good foundation. Two points before you watch. At around the point where the plan is set out the tutor ranks B first and then says “produce as many A’s as we can, which is 10,000” — he means B; the arithmetic he then does is B’s, and the notes and the answer below have it right (10,000 B, then 19,000 A). The assumption behind the $80,000 of fixed costs is explained in the recording and is written out in section 3.4 and in Answer 1 below.

YouTube video

Conventional limiting factor analysis

Pi plc manufactures 2 products, A and B.

The cost cards are as follows:

$ per unit

A

B

Selling price

25

28

Materials

8

20

Labour

5

2

Other variable costs

7

2

Fixed costs absorbed

3

2

Total cost

23

26

Profit per unit

2

2

Machine hours per unit

2

1

Maximum demand (units)

20,000

10,000

The total machine hours available are 48,000.

Calculate the optimum production plan and the maximum profit using conventional limiting factor analysis.

Show answerHide answer

Conventional limiting factor analysis

Step 1 — is machine time a limiting factor?

Full demand would need (20,000 × 2) + (10,000 × 1) = 50,000 hours against 48,000 available. It is.

Step 2 — contribution per unit, and per machine hour

$ per unit

A

B

Selling price

25

28

Materials

(8)

(20)

Labour

(5)

(2)

Other variable costs

(7)

(2)

Contribution per unit

5

4

Machine hours per unit

2

1

Contribution per machine hour

$2.50

$4.00

Ranking

2nd

1st

Step 3 — the production plan

Units

Hours each

Hours used

Hours left

Hours available

48,000

B (1st) — capped at maximum demand

10,000

1

10,000

38,000

A (2nd) — 38,000 ÷ 2 hours

19,000

2

38,000

nil

48,000

Produce 10,000 units of B and 19,000 units of A. A is 1,000 units short of its demand; B is met in full.

Step 4 — the maximum profit

$

Contribution: A

19,000 × $5

95,000

Contribution: B

10,000 × $4

40,000

Total contribution

135,000

Fixed costs: A

20,000 × $3

(60,000)

Fixed costs: B

10,000 × $2

(20,000)

Maximum profit

55,000

Assumption — the fixed cost per unit on the cost card was set on budgeted output of 20,000 A and 10,000 B, i.e. full demand, before the machine-hour limit was known. Total fixed costs are therefore $80,000 and stay at $80,000 whatever the plan produces.

4 Theory of constraints and throughput accounting

4.1 The theory of constraints

Goldratt’s theory of constraints starts from the observation that a system’s output is set by its slowest step. That step is the bottleneck. Improving anything else does not increase output; it only builds inventory in front of the bottleneck. So management should organise everything else around the bottleneck to keep it working, and then work to remove it — at which point some other step becomes the bottleneck and the exercise begins again.

Goldratt measures performance by throughput — the rate at which the system turns purchases into sales revenue — rather than by output or by unit cost, because producing something that has not been sold generates no money at all.

4.2 The throughput assumption

Over the next week or month, most organisations cannot change their labour force: the same people are paid whether the week is busy or slack. The same is true of most of what is normally called variable overhead. Materials are different — make fewer units and you buy less material.

Throughput accounting therefore assumes that in the short term the only variable cost is direct material, and that every other production cost — labour included — is fixed. Those other costs, added together, are the total factory cost.

The measure that replaces contribution is throughput:

Throughput = Sales revenue − Direct material cost

and the ranking rule is unchanged in form — rank by throughput per unit of the bottleneck resource, which is called the return per factory hour:

Return per factory hour = Throughput per unit ÷ Bottleneck hours per unit

4.3 Cost per factory hour and the throughput accounting ratio

The cost of running the factory for one bottleneck hour is the total factory cost spread over the bottleneck hours available:

Cost per factory hour = Total factory cost ÷ Total bottleneck hours available

Comparing the two gives the throughput accounting ratio (TPAR):

TPAR = Return per factory hour ÷ Cost per factory hour

Interpreting the ratio

  • A TPAR greater than 1 means an hour of the bottleneck spent on that product returns more than it costs to run the factory for that hour. The product is viable.

  • A TPAR less than 1 means the reverse: that hour loses money.

  • The higher the ratio the better the product, so the TPAR ranking is the same ranking as return per factory hour — it carries no new information about the ordering, only about viability.

A ratio below 1 can be improved in four ways, and each is worth naming because they are the four terms in the ratio:

  • raise the selling price (raises throughput per unit);

  • reduce the material cost per unit (raises throughput per unit);

  • reduce the time the product spends on the bottleneck (raises return per factory hour);

  • reduce the total factory cost (lowers cost per factory hour).

A TPAR below 1 is not an instruction to withdraw the product. Products are often sold as a range, or together, and a customer who cannot buy one may buy neither. A low price may be deliberate — a loss leader, penetration pricing, or an introductory price. And withdrawing a product only helps if the bottleneck hours it frees can be used for something better; if there is nothing else to make, the hours are simply idle and the factory cost is incurred anyway. Chapter 14 takes discontinuation decisions properly.

This lecture takes Example 1’s figures again on the throughput assumption and works Example 2 below: throughput of $17 and $8 a unit, a return per factory hour of $8.50 and $8.00, a plan of 20,000 A and 8,000 B, a total factory cost of $360,000 and a profit of $44,000, then the reasons for keeping a product whose ratio is below 1. Two points before you play it.

Check one figure against Answer 2: the throughput accounting ratios are 1.13 for A and 1.07 for B ($8.00 ÷ $7.50). Both are above 1, which is the point the recording goes on to make.

Coverage: it does not teach the theory of constraints in section 4.1 — the bottleneck and Goldratt’s measure of throughput. Read that section on its own.

YouTube video

Beyond P1. P1C3c asks for product mix decisions with constraints, and the examinable core of this chapter is the ranking rule — contribution, or throughput, per unit of the scarce resource. The throughput accounting ratio and the wider theory of constraints are developed at P2. They are kept here because they are the same argument under a different cost assumption, and because the lecture teaches them.

Throughput accounting

Pi plc manufactures 2 products, A and B. The cost cards are the same as in example 1:

$ per unit

A

B

Selling price

25

28

Materials

8

20

Labour

5

2

Other variable costs

7

2

Fixed costs absorbed

3

2

Total cost

23

26

Profit per unit

2

2

Machine hours per unit

2

1

Maximum demand (units)

20,000

10,000

The total machine hours available are 48,000. Machine time is the bottleneck resource.

(a) Calculate the optimum production plan and the maximum profit, on the assumption that in the short term only material costs are variable, i.e. using a throughput accounting approach.

(b) Calculate and interpret the throughput accounting ratios (TPAR) for A and B.

(c) Suggest some business reasons why management might decide NOT to withdraw an unprofitable product from sale.

Show answerHide answer

Throughput accounting

(a) Throughput per unit, and the plan

$ per unit

A

B

Selling price

25

28

Materials (the only variable cost)

(8)

(20)

Throughput per unit

17

8

Machine hours per unit

2

1

Return per factory hour

$8.50

$8.00

Ranking

1st

2nd

The ranking has reversed. Labour and other variable costs are no longer deducted, and B carries much more of them than A ($4 against $12), so removing them helps A far more than B.

Units

Hours each

Hours used

Hours left

Hours available

48,000

A (1st) — capped at maximum demand

20,000

2

40,000

8,000

B (2nd) — 8,000 ÷ 1 hour

8,000

1

8,000

nil

48,000

Total factory cost — everything except materials, on the same budgeted output of 20,000 A and 10,000 B:

Per unit $

Budgeted units

$

A: labour 5 + other variable 7 + fixed 3

15

20,000

300,000

B: labour 2 + other variable 2 + fixed 2

6

10,000

60,000

Total factory cost

360,000

Profit

$

Throughput: A

20,000 × $17

340,000

Throughput: B

8,000 × $8

64,000

Total throughput

404,000

Total factory cost

(360,000)

Maximum profit

44,000

(b) Throughput accounting ratios

Cost per factory hour = $360,000 ÷ 48,000 hours = $7.50 per hour.

A

B

Return per factory hour

$8.50

$8.00

Cost per factory hour

$7.50

$7.50

TPAR

1.13

1.07

Both ratios exceed 1, so both products return more per bottleneck hour than the factory costs to run for that hour, and both are viable. A’s ratio is the higher, which is why the plan gives A the hours first and B takes only what is left over.

(c) Reasons for keeping an unprofitable product

  • the products may be sold together as a range, so dropping one loses sales of the others;

  • the low price may be deliberate — a loss leader, an introductory price, or a penetration price intended to build the market;

  • the freed bottleneck hours may have no better use, in which case they are simply idle and the factory cost is unchanged;

  • the product may be at an early stage of its life cycle and expected to improve;

  • withdrawal may damage relationships with customers, or with the distribution channel.

Three products, one scarce material

Kappa Co makes three products, X, Y and Z. All three use material M, which costs $2 per kg. Only 6,000 kg of M can be obtained next period. There are no other constraints.

$ per unit

X

Y

Z

Selling price

40

30

55

Material M

8

6

20

Other variable costs

17

14

15

Fixed overhead absorbed

6

5

8

Total cost

31

25

43

Profit per unit

9

5

12

Maximum demand (units)

500

800

300

(a) Prepare the optimum production plan and calculate the profit it earns.

(b) A second supplier will sell Kappa Co additional material M at $3.20 per kg. State, with a calculation, how many extra kilograms Kappa Co should buy.

Show answerHide answer

Three products, one scarce material

(a) Material M costs $2 per kg, so the kilograms per unit are the material cost per unit divided by $2: X 4 kg, Y 3 kg, Z 10 kg.

Full demand would need (500 × 4) + (800 × 3) + (300 × 10) = 2,000 + 2,400 + 3,000 = 7,400 kg against 6,000 kg available, so M is a limiting factor.

$ per unit

X

Y

Z

Selling price

40

30

55

Material M

(8)

(6)

(20)

Other variable costs

(17)

(14)

(15)

Contribution per unit

15

10

20

Kilograms of M per unit

4

3

10

Contribution per kg of M

$3.75

$3.33

$2.00

Ranking

1st

2nd

3rd

Note that Z has both the highest contribution per unit and the highest profit per unit on the cost card, and is nevertheless the worst use of the scarce material.

Units

kg each

kg used

kg left

Available

6,000

X (1st) — maximum demand

500

4

2,000

4,000

Y (2nd) — maximum demand

800

3

2,400

1,600

Z (3rd) — 1,600 ÷ 10

160

10

1,600

nil

6,000

$

Contribution: X

500 × $15

7,500

Contribution: Y

800 × $10

8,000

Contribution: Z

160 × $20

3,200

Total contribution

18,700

Fixed overhead (500 × $6) + (800 × $5) + (300 × $8)

(9,400)

Profit

9,300

(b) Extra material would be used on the best unsatisfied product, which is Z. A kilogram used on Z earns $2.00 of contribution — and that figure is already net of material at the normal $2 per kg. The extra kilogram costs $1.20 more than normal, so the net gain is $2.00 − $1.20 = $0.80 per kg.

Buying is therefore worthwhile, but only up to the point where Z’s demand is met. Z needs 3,000 kg in total and has 1,600 kg, so Kappa Co should buy 1,400 kg, gaining 1,400 × $0.80 = $1,120. Beyond that there is no unsatisfied demand and the extra material would earn nothing.

The $2.00 contribution per kg of the best unsatisfied use is the shadow price of material M — the most Kappa Co would pay, over and above the normal price, for one more kilogram. Chapter 8 calculates shadow prices where there is more than one constraint.

5 The two approaches compared

Examples 1 and 2 use identical data and reach opposite rankings. That is not a contradiction: they answer the same question under different assumptions about which costs vary in the short term. Neither profit figure is “the” profit; each is the profit consistent with its own assumption.

Conventional (marginal)

Throughput

What varies in the short term

Materials, labour and other variable costs

Materials only

Measure per unit

Contribution — price less all variable costs

Throughput — price less material cost

Ranked on

Contribution per unit of the limiting factor

Return per factory hour

Ranking here

1st B, 2nd A

1st A, 2nd B

Plan

10,000 B and 19,000 A

20,000 A and 8,000 B

Profit on its own assumption

$55,000

$44,000

The test that each ranking really is best under its own assumption is to cost the other plan the same way:

Conventional plan

Throughput plan

Profit on the marginal assumption

$55,000

$52,000

Profit on the throughput assumption

$43,000

$44,000

(Throughput plan on the marginal assumption: contribution (20,000 × $5) + (8,000 × $4) = $132,000, less $80,000 fixed = $52,000. Conventional plan on the throughput assumption: throughput (19,000 × $17) + (10,000 × $8) = $403,000, less $360,000 total factory cost = $43,000.) Each plan wins under its own assumption — so in an exam question the assumption stated in the requirement decides the method, and the two are never mixed.

6 Test your knowledge

Two quick checks before you move on: work through the flashcards to fix this chapter’s key terms and definitions, then sit the objective questions for exam-style practice. Both mark themselves and explain the answers as you go.

Practice questions

Limiting Factor Analysis and throughput accounting

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