2) The percentage probability that a student will score more than 90 marks in an accounting exam is 2.28%. The marks scored from the accounting exam follow a standard normal distribution with a mean mark of 70.
What is the standard deviation for the distribution?
Answer = Z = (x – µ)/?
2.28 = (90-70)/?
0.4887 = 20/?
? = 20/0.4887
? = 40.92
Mr Moffat can you please tell me if my answer is correct and can you please help me correct it if its wrong, i found this in the ACCA practice test and we're not given the answers for it. Thanks a lot Mr Moffat, May god bless you.
MAstandard deviation
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Oh okay Sir, Thank you for letting me know :)
You are welcome.