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Measures of dispersion example 4

AAnnelise8y ago
Hi It seems there was a calculation error when calculating the variance. The squeare of 0.46(the difference between the observation 2 and the arthmetic mean 1.54) is 0.21. Then the frequency(4) multiplied by 0.21 equals 0.84 and not 0.17? Can you please let me know wheter I misunderstood? Regards Annelise
John MoffatJohn MoffatTutor8y ago#1
You are correct and I must re-record the lecture - thank you for spotting it. However the answer at the back of the free lecture notes is correct (although the figure for 3 complaints is wrong due to a typing mistake - but the final answer is correct) I will have that corrected as well!
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