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Hi My Dear Tutor, I have a question.
example 2 In your open tuition lecture note’s quantity analysis chapter,it says how long will it take to produce an extra 7 units?
Doubling method.
Total time for 8 units—–337.5
total time for 1 unit—-(100)
total time for 7 units–237.5when i did it by using log method it gave me 312.141 why i do not get the same answer with doubling?the same thing i also checked in example 3 for 15 bathches, i used doubled method and log method
total time for 16 bathces—1670.416
total time for 1 batche—(200)
total time for 15 batches——–1470.416with log method i got 1589.90
I have no idea why you are getting different answers – you must be using the formulae wrongly.
The formula gives exactly the same answer (in the second case there is a tiny difference – 1670.26 instead of 1670.42 – but this is simply due to rounding and is irrelevant).
Are you remembering that b is all cases is negative?
Yes log 0.85/log2= -0,0705810743/0.3010299957=-0,2344652537
———————-average time per unit
15*———105.9930673=1589.8960095y=200*15^-0.2344652537=105.9930673
To get the average time per batch for 16 batches, it is 200 x 16^-0.2345, which is 104.39
So the total time for 16 batches = 16 x 104.39 = 1670
They have already made 1 batch and so if they make another 15 then they will then have made 16. So the time for the next 15 is the total time for 16 less the time for the first.
The more they have already made, then the faster it will be to make more.
I explain all this in my lecture.
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