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ACCA P4 Share Options and Option Pricing part 1

VIVA

ACCA P4 lectures Download P4 notes

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Comments

  1. iq2k16 says

    November 30, 2016 at 5:06 am

    A very basic question: Value of an option is basically the premium payable right?

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    • John Moffat says

      November 30, 2016 at 5:32 am

      Yes 🙂

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  2. sunday says

    September 22, 2016 at 4:58 pm

    Thanks alot

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  3. alpha2006 says

    July 2, 2016 at 2:20 pm

    Hello sir…
    am confused, why do u said the call option is cheaper than the put option in this case?
    the call option 5cent n the put option 28cent

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    • John Moffat says

      July 2, 2016 at 7:22 pm

      The prices of the two options depend on how likely they are to end up being exercised.

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  4. saan says

    January 15, 2016 at 2:01 pm

    @ Sir John Moffat,

    Sir I was doing ‘Q59 UNIGLOW from Kaplan kit sep14 to aug15 edition’ on option pricing.
    It is not difficult question but I just need to understand one point.
    In answer it says we can use Delta to construct delta hedge and in order to protect against a fall in Uniglow’s share price, the easiest hegde would be to write (sell) options on Uniglow’s shares. (I am protecting the investment of my company in Uniglow’s shares).
    So my question whether the option we sell is call or put option?

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    • John Moffat says

      January 15, 2016 at 3:56 pm

      We sell a call option (you could achieve the same ‘protection’ by buying a put option, but in the exam you always sell a call to create a delta hedge, unless told otherwise).

      I do explain the reasoning behind this in the lectures.

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      • saan says

        January 16, 2016 at 11:04 am

        Thank you very much sir.

      • John Moffat says

        January 16, 2016 at 3:06 pm

        You are welcome 🙂

  5. Vione says

    November 26, 2015 at 9:43 am

    thank you. incredible lecture

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    • John Moffat says

      November 26, 2015 at 11:37 am

      Thank you for the comment 🙂

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  6. accafreak91 says

    November 14, 2015 at 8:37 am

    i still can’t figure out how you reached the figure of 0.045 while calculating d1 (0.1+0.5*0.4^2)0.25 . My answer is 0.105 i’m really confused please help..

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    • John Moffat says

      November 14, 2015 at 8:39 am

      (0.1 + 0.5 x 0.4 x 0.4) x 0.25 = (0.1 + 0.08) x 0.25 = 0.18 x 0.25 = 0.045

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      • accafreak91 says

        November 14, 2015 at 8:49 am

        thank you so much looks like my calculator had issues

      • John Moffat says

        November 14, 2015 at 8:58 am

        You are welcome 🙂

  7. sogan0 says

    May 26, 2015 at 3:26 pm

    on example 5 why is the put option more epensive than call option?

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    • John Moffat says

      May 26, 2015 at 5:44 pm

      Because that is was comes out of the equations!!!!

      The price of the share in 3 months could obviously be anything. However it is more likely that it will be less than 1.80 than more than 1.80, so the people selling the options will want to charge more for a put option because they are more likely to have to pay out on it.

      (and don’t ask me why the price is more likely to be less than 1.80 than more!! That is down to the statistics why is how the derived the formulae, and I have certainly no intention of going through their proof 🙂 )

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  8. kash says

    May 19, 2015 at 8:26 pm

    am unable to calculator the figure for e.
    I have a scientific one with e and ln.
    which key to press for +-

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    • John Moffat says

      May 19, 2015 at 8:56 pm

      Not all scientific calculators are the same – there are two different ways that they work. If yours does not have a +/- button then it uses a different logic, and you will have to look in the instruction book how to do it.

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    • drice99 says

      January 13, 2018 at 8:42 pm

      in mine i just type shift, e^x,-.25 etc. mine doesnt have a +/- button either but it still works by just typing ‘-‘ before any figure

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  9. waqas says

    April 13, 2015 at 8:03 am

    Sir,
    In Example % while calculating value of call option on the third step u used e raised to power -.04… aint that wrong as time is .25 and r is .1 when we multiply that it comes to .025.. :O
    dont know how u came to to .04 :O
    waiting for ur reply
    thanks

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    • waqas says

      April 13, 2015 at 8:04 am

      example 5

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      • John Moffat says

        April 13, 2015 at 10:31 am

        You are correct – it should be 0.025 (and the final answer should be 4c).
        I will re-record the lecture.

      • waqas says

        April 13, 2015 at 12:47 pm

        thanks 🙂

      • braske77 says

        May 25, 2015 at 5:19 pm

        Please leave it like it is, makes us think, not just silly writing all down 🙂

      • John Moffat says

        May 25, 2015 at 5:24 pm

        Good point Braske77 (and thank you 🙂 )

  10. sogan0 says

    February 24, 2015 at 3:49 pm

    Im gettign lost in example 5 on the calculation of p on the e to the power of -0.04 what is the e value is it 2.7183

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    • John Moffat says

      February 24, 2015 at 4:05 pm

      Yes it is – and you must have a calculator with an ‘e’ button on it 🙂

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      • sogan0 says

        March 14, 2015 at 6:58 pm

        found the e button thanx

  11. sogan0 says

    February 24, 2015 at 3:47 pm

    Hi Tutor

    Please give me an example on how to use the distribution table i got lost in Example 5 on the column 0.09 why that column?

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    • John Moffat says

      February 24, 2015 at 4:03 pm

      I assume you were happy in arriving at the figure of -0.6886 for D1 (the workings are at the end of the lecture notes as well).

      We look up 0.69 in the tables (we can only look up for 2 decimal places, so 0.6886 becomes 0.69). So do this you look along the 0.6 row and as you move through the columns it gives the figure for 0.60, 0.61, 0.62 and so on. We want 0.69 and so it is the 0.6 row and the 0.09 column, and the figure from the tables is 0.2549.

      Because D1 is negative, we subtract then 0.2549 away from 0.5.
      (Had it been positive, as D2 is, then we would add 0.5). This rule is given at the bottom of the tables.

      You should be able to follow the rest of the answer at the back of the Lecture Notes.

      (How did you manage to sort out the first four examples, but not example 5? :-))

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      • sogan0 says

        March 14, 2015 at 7:00 pm

        i only started practicing exmaple 5 then i got lost. Many thanx for your advice

  12. questforknowledge says

    November 7, 2014 at 2:11 pm

    John i have this question. it concerns calculatind d1 if a questions is given n i calculate d1 and a figure say 1.2812 and i then round it to 1.28 and another candidate calculates his and round it to 1.3. these two answers will give different values for N(d1) which will lead to a different value for a call option. will the two of us have all the marks. I am asking because when calculating the figure for natual log of Pa/Pe due to rounding candidates will have different answers
    thank you

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    • John Moffat says

      November 7, 2014 at 5:25 pm

      Two things.

      Firstly most if not all of the marks are for proving you understand what is happening rather than for the final answer.
      Secondly, when rounding you should really round to the number of decimals needed for the tables, so why round to 1.3 when the tables allow you to look up 1.28 🙂

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  13. mustafabilalqari says

    May 28, 2014 at 2:03 am

    How can I Have Lectures of Business Valuation

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    • John Moffat says

      May 28, 2014 at 5:45 am

      There are no lectures yet on business valuation.

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  14. ALI says

    November 23, 2013 at 7:57 am

    How can i download this?or this is only for watching?

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    • John Moffat says

      November 23, 2013 at 7:59 am

      I am sorry, but you can only download the course notes – the lectures can only be watched online.
      It is the only way that we can keep this website free of charge.

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      • ALI says

        November 23, 2013 at 8:07 am

        Can u provide me solution of paper strategic financial management 3.7 of december 2006 of ACCA………?

      • John Moffat says

        November 23, 2013 at 8:11 am

        I don’t think that I have it any longer – I will check later.
        Do remember that the examiner (and the syllabus) has changed twice since then.

      • ALI says

        November 23, 2013 at 12:38 pm

        okk,,,..

  15. NEENA says

    November 14, 2013 at 6:57 pm

    sir in example you taken t as 0.4 in formula of call option and put option i guess thats a mistake it should be 0.25 right?

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    • NEENA says

      November 14, 2013 at 6:57 pm

      i mean example 5.

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      • John Moffat says

        November 14, 2013 at 8:36 pm

        I have watched my lecture again, and it seems that I have taken ‘t’ as 0.25 correctly (it is ‘s’ that is 0.4).

        You can of course check the answer at the back of the Course Notes. I think it is correct.

      • Lidia says

        December 1, 2013 at 1:51 pm

        Dear John, it seems when calculating ‘-rt’ in example 6 (52,48 minute of the lecture and so on) you’ve multiplied 0,1 (r) by 0,4 instead of 0,25 (t)….

      • John Moffat says

        December 1, 2013 at 1:58 pm

        Ooops – you are correct.
        Sorry 🙁

  16. sakura69 says

    October 16, 2013 at 4:52 am

    Thanks John!

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  17. ruth12 says

    September 4, 2013 at 1:04 am

    These are very well explained lectures and are a great help. Thank you sir and Open Tuition.

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  18. toobaalvi says

    June 1, 2013 at 1:39 am

    I have a very basic ques.. But its really confusing me. why the value of option is share price – excercise price?

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    • John Moffat says

      June 1, 2013 at 4:10 pm

      If it was a call option exercisable immediately, then the option gives you the right to buy a share at a fixed price.

      So, for example, if the current share price is $4.00 and you could buy an option giving you the right to buy the share at an exercise price of $3.70, then you could buy the share for $3.70 and immediately sell it for $0.30.
      Nobody is going to give you that right free! You would be prepared to pay $0.30 for the option. Then you could use it and buy a share for $3.70. You have then spent $4.00 in total and you own a share worth $4.00 🙂

      (But of course, that is only if the option were exercisable immediately. In practice the option will be the right to buy a share at a fixed price on a future date, and to get the value of that we need to use all the formulae.)

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  19. tinashe says

    May 31, 2013 at 8:35 pm

    thank u!

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  20. tinashe says

    May 31, 2013 at 8:34 pm

    thank you

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