Sir, my question is VAR at 90%, 10% of unconfident, so 0.5 -0.1=0.4. Then, when I look into the std normal distribution table my answer = 1.289 from 0.08 (0.3997) & 0.09 (0.4015) at 1.2 .
But the answer in the Q3 Dec 2014 is 1.282 for 90%, how could I find it?
1.28 gives 0.3997 and 1.29 gives 0.4015, and therefore to get 0.4 is between the two and we just apportion between them assuming there is a linear relationship.
The difference between 0.3997 and 0.4015 is 0.0018.
To get 0.4 we need to be 0.0003 above 0.3997, and so apportioning gives an answer of 1.28 + (0.0003/0.0018 x (1.29 – 1.28)) = 1.282
However, I would not spend time apportioning and would just choose the nearest (in the case 1.28). I do not believe that taking 1.28 would lose any marks at all 🙂