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VAR std deviation

Forums › Ask ACCA Tutor Forums › Ask the Tutor ACCA AFM Exams › VAR std deviation

  • This topic has 1 reply, 2 voices, and was last updated 4 years ago by John Moffat.
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  • January 16, 2021 at 9:00 am #606078
    joynow
    Member
    • Topics: 42
    • Replies: 38
    • ☆☆

    Sir, my question is VAR at 90%, 10% of unconfident, so 0.5 -0.1=0.4. Then, when I look into the std normal distribution table my answer = 1.289 from 0.08 (0.3997) & 0.09 (0.4015) at 1.2 .

    But the answer in the Q3 Dec 2014 is 1.282 for 90%, how could I find it?

    January 16, 2021 at 10:43 am #606098
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54699
    • ☆☆☆☆☆

    We need a result from the tables of 0.4.

    1.28 gives 0.3997 and 1.29 gives 0.4015, and therefore to get 0.4 is between the two and we just apportion between them assuming there is a linear relationship.

    The difference between 0.3997 and 0.4015 is 0.0018.

    To get 0.4 we need to be 0.0003 above 0.3997, and so apportioning gives an answer of
    1.28 + (0.0003/0.0018 x (1.29 – 1.28)) = 1.282

    However, I would not spend time apportioning and would just choose the nearest (in the case 1.28). I do not believe that taking 1.28 would lose any marks at all 🙂

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