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two data variable with stepup cost …urgent!!!!!!!!!!!!!!!!!!!!!

Forums › ACCA Forums › ACCA MA Management Accounting Forums › two data variable with stepup cost …urgent!!!!!!!!!!!!!!!!!!!!!

  • This topic has 3 replies, 3 voices, and was last updated 15 years ago by AvatarAnonymous.
Viewing 4 posts - 1 through 4 (of 4 total)
  • Author
    Posts
  • February 17, 2011 at 2:09 pm #47414
    Avatarmulo
    Member
    • Topics: 1
    • Replies: 6
    • ☆

    A company has the following costs at three activity levels.
    Activity 60000 72000
    Total cost 960000 1104000
    The fixed cost is constant over this range of activity, but there is a reduction in the variable cost per unit by 10% when the activity level exceeds 15,000 units. This reduction applies to all units.
    What is the expected total cost when the activity level is 14,000 units?
    A $131,800
    B $132,400
    C $136,000
    D $138,000
    correct answer is D

    can some plz explain?

    February 23, 2011 at 12:04 am #77296
    AvatarAnonymous
    Inactive
    • Topics: 0
    • Replies: 3
    • ☆

    I just tried to solve this but I couldn’t. I think the numbers are incorrect, however if they are correct, I cannot explain it.
    Good luck,
    B.

    March 17, 2011 at 9:53 am #77297
    AvatarAnonymous
    Inactive
    • Topics: 0
    • Replies: 4
    • ☆

    i can solve this problem as………………………1) u typed wrong activity level as 60000 and 72000 but if it is as 6000 and 7200 then i can explain this step by step……………………concentrate here……………

    1)identify thehighest and lowest activity level …………………high is 7200 and low is 6000

    2)now find v.c/unit wid the formula as=cost at high activity level -cost at low activity level and divide this wid…high activity level -low activity level

    so the v.c/unit will be showed as……….1104000-960000=144000 and divide this wid this,,,,,,,,,7200-6000=1200/…………..144000 divide 1200=120 v.c/unit

    t.v.c=v.c/unit x highest or lowest activity level(depends on u …….that u will high or low)i will high………………
    t.v.c=120×7200=864000

    now f.c=t.c-t.v.c
    f.c=(highest cost)110400-864000=240000

    so tc is equal to f.c+t.v.c
    t.c=240000+864000=1104000

    we find these at 7200 activity level but we need to find at 14000

    so t.c at 14000:::::::::::::::
    t.c=f.c+(v.c/unit x no. of units find)
    t.c=240000+ (120 x 14000)
    t.c=240000+1680000
    t.c=1920000…………………

    March 17, 2011 at 9:59 am #77298
    AvatarAnonymous
    Inactive
    • Topics: 0
    • Replies: 4
    • ☆

    but if units exceed from 15000 units then v.c/unit will decrease asssss then v.c/unit which is 120 x 10/100==108

    now again f.c+(v.c/unit x units find)
    t.c=240000+(108 x 14000)
    t.=240000+1512000
    t.c=1752000

    so i explained thanks…………..

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