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Total costs

Forums › Ask ACCA Tutor Forums › Ask the Tutor ACCA MA – FIA FMA › Total costs

  • This topic has 6 replies, 2 voices, and was last updated 2 years ago by John Moffat.
Viewing 7 posts - 1 through 7 (of 7 total)
  • Author
    Posts
  • July 15, 2022 at 9:21 pm #660629
    Safiya.12345
    Participant
    • Topics: 65
    • Replies: 117
    • ☆☆

    A company has been reviewing its total costs over the last few periods and has established the
    Period 1,2,3
    Sales units 225,150,350
    Total cost
    2300,1500,2800 respectively

    The company is aware that fixed costs increase by £500 when sales exceed 200 units.
    Ans 1620

    July 15, 2022 at 9:24 pm #660630
    Safiya.12345
    Participant
    • Topics: 65
    • Replies: 117
    • ☆☆

    Sir shouldn’t the ans be 2120
    2800-1500-500/350-150= 4
    Fc is 2800-(350×4)=1400
    Total costs
    180×4 +1400=2120
    Your feedback would be really helpful

    July 16, 2022 at 9:59 am #660665
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54655
    • ☆☆☆☆☆

    You have not typed what the question is asking for.

    July 16, 2022 at 10:07 am #660667
    Safiya.12345
    Participant
    • Topics: 65
    • Replies: 117
    • ☆☆

    Total cost at sales level of 180 units

    July 16, 2022 at 10:15 am #660672
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54655
    • ☆☆☆☆☆

    The fixed cost that you have calculated of 1,400 is for levels above 200 units.

    180 units is below 200 units and therefore the fixed cost is $500 lower and is only $900.

    July 16, 2022 at 1:45 pm #660679
    Safiya.12345
    Participant
    • Topics: 65
    • Replies: 117
    • ☆☆

    Sir r if TC ay 200 units is asked then Fc would be 1500-(150×4) 900 since 500 increase only of sales exceed 200 units

    July 16, 2022 at 3:37 pm #660684
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54655
    • ☆☆☆☆☆

    Correct.

  • Author
    Posts
Viewing 7 posts - 1 through 7 (of 7 total)
  • The topic ‘Total costs’ is closed to new replies.

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