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Chapter 3 Illustration 3/pg 61 study text Kaplan compund instrument

Forums › CIMA Forums › Chapter 3 Illustration 3/pg 61 study text Kaplan compund instrument

  • This topic has 1 reply, 2 voices, and was last updated 6 years ago by P2-D2.
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    Posts
  • March 17, 2020 at 5:35 pm #565355
    aura
    Participant
    • Topics: 2
    • Replies: 0
    • ☆

    Can you help me understand what is the logic behind the calculation in the 3rd step (conversion of the bond) in Illustration 3/page 64 study text kaplan- they say like this:
    “the conversion terms sre two 25c shares for every $1, so $50m x 2 = $100 m shares which have a nominal value of $25m” why do they multiply with 2 and not with 2.25 ? How they get to $25m nominal value?
    thanks a lot.

    March 19, 2020 at 9:34 am #565414
    P2-D2
    Keymaster
    • Topics: 4
    • Replies: 7231
    • ☆☆☆☆☆

    Hi,

    It is a bit confusing but I’d think of it as follows:

    Two shares are issued for every $1 owed – so $50m is owed so we will issue 100 million shares ($50m/$1 x 2 shares).

    Each share has a nominal value of 25c – so the nominal value of the 100 million shares issued is $25 million (100 million shares x $0.25 nominal value)

    Hope that clears it up for you.

    Thanks

    Chris

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