ammar Active 4 years agoTopics: 0Replies: 1☆ProfileForumsTopics StartedReplies CreatedEngagementsForum Replies CreatedViewing 1 post (of 1 total)AuthorPosts September 6, 2017 at 8:20 pm #406204 ammarMemberTopics: 0Replies: 1☆i did it like this. At first i thought of finding the value of a by using MR=a-2bq but then i went with the approch of P=a-bq placing 0 as value of ‘P’AuthorPostsViewing 1 post (of 1 total)