Protected: ammar Active 6 years ago Topics: 0Replies: 1☆ ProfileForums Topics StartedReplies CreatedEngagements Forum Replies Created Viewing 1 post (of 1 total) Author Posts September 6, 2017 at 8:20 pm #406204 ammarMember Topics: 0Replies: 1☆ i did it like this. At first i thought of finding the value of a by using MR=a-2bq but then i went with the approch of P=a-bq placing 0 as value of ‘P’ Author Posts Viewing 1 post (of 1 total)
