Hi Sir
I am getting confused in the question below, can you please help me solve it
A chemical flavouring, product C is made by mixing two materials together:
Standard – Kg per batch – $ per kg – $ per batch
L – 300 – $1.30 – 390
H – 500 – $2.82 – 1,410
Input per batch 800kg
10% standard loss 80kg
Output per batch 720kg
For batch 1247 input as 250.5kg of L and 669.5kg of H. Output from the batch was 810kg of product C.
What is the yeild variance?
I am getting confused with the 10% loss part.
Thank you in advance!
ACCA Forums
PMYield Variance Question
5y ago#1For the yield variance compare the actual total input (920kg) with the standard total input for the actual production (810 x 800/720 = 900 kg), in both cases at standard mix (300/800 for L, and 500/800 for H) and at standard cost.
Have you watched my free lectures on mix and yield variances?
Sir, I got two different answers.
When I did it in Tabular form, I got the answer as 177.339 A
and when I did it this way (below) I got it as 45A.
920kg of Input Produced 810kg
920Kg of input should have produced 828kg
Yeild= 18x2.5 = 45A.
Please tell me where have I gone wrong.
5y ago#3Why are you attempting a question for which you do not have an answer? You should be using a Revision Kit from one of the ACCA Approved Publishers - they have answer :-)
I cannot tell you where you have gone wrong because I cannot see your workings to be able to check.
Again I ask, have you watched my free lectures on this?
Sir, I understood my mistake.
Sorry, for the trouble.
Thank you!
5y ago#5You are welcome :-)
This topic is locked — no new replies.