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Time series analysis question

Forums › Ask ACCA Tutor Forums › Ask the Tutor ACCA PM Exams › Time series analysis question

  • This topic has 3 replies, 2 voices, and was last updated 4 years ago by John Moffat.
Viewing 4 posts - 1 through 4 (of 4 total)
  • Author
    Posts
  • December 15, 2021 at 1:29 am #644268
    letty23
    Participant
    • Topics: 10
    • Replies: 8
    • ☆

    In a time series analysis, the multiplicative model is used to forecast sales and the following
    seasonal variations apply:

    Quarter 1 2 3 4
    Seasonal variation 1.3 1.4 0.5 ?

    What is the seasonal variation for the fourth quarter (to one decimal place)?

    Can you please explain me why they deducted the SV of the first 2 quarters then multiply the SV of Quarter 3? I know it is the multiplicative model but I am confused about the logic of this.

    Let x = seasonal variation in quarter 4.
    1.3 + 1.4 + 0.5 + x = 4
    Therefore x = 4 – 1.3 – 1.4 x 0.5 = 0.8

    Thank you.

    December 15, 2021 at 8:25 am #644280
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54836
    • ☆☆☆☆☆

    Have you checked the arithmetic? Because what you have typed does not equal 0.8 at all – either you have copied the answer wrongly or your book has a typing error in it. Which Revision Kit are you using? (BPP or Kaplan).

    The seasonal variations must add up to 4 in total. The first three add up to 1.3 + 1.4 + 0.5 = 3.2

    Therefore the seasonal variation in quarter 4 must be 4 – 3.2 = 0.8.

    December 16, 2021 at 2:07 am #644375
    letty23
    Participant
    • Topics: 10
    • Replies: 8
    • ☆

    Yes, I did. The answer is like that so I believe there is a typing error in it. I am using BPP Revision Kit.

    Thank you, I have understood it now.

    December 16, 2021 at 7:13 am #644384
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54836
    • ☆☆☆☆☆

    You are welcome.

  • Author
    Posts
Viewing 4 posts - 1 through 4 (of 4 total)
  • The topic ‘Time series analysis question’ is closed to new replies.

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