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Target costing

Forums › ACCA Forums › ACCA PM Performance Management Forums › Target costing

  • This topic has 1 reply, 2 voices, and was last updated 1 month ago by gohar181.
Viewing 2 posts - 1 through 2 (of 2 total)
  • Author
    Posts
  • March 8, 2025 at 11:17 pm #716046
    artty
    Participant
    • Topics: 1
    • Replies: 0
    • ☆

    Component 2 (Wiring) – in an ideal situation 25 cm of wiring is needed for each completed radio. However, there is
    some waste involved in the process as wire is occasionally cut to the wrong length or is damaged in the assembly
    process. Edward Co estimates that 2% of the purchased wire is lost in the assembly process. Wire costs $0·50 per
    metre to buy.

    Assembly labour – these are skilled people who are difficult to recruit and retain. Edward Co has more staff of this
    type than needed but is prepared to carry this extra cost in return for the security it gives the business. It takes 30 minutes to assemble a radio and the assembly workers are paid $12·60 per hour. It is estimated that 10% ofhours paid to the assembly workers is for idle time.

    Someome help to Calculate labour per hr and meterial per unit

    April 6, 2025 at 12:12 pm #716478
    gohar181
    Participant
    • Topics: 6
    • Replies: 1
    • ☆

    1. Material Cost per Unit (Wiring)
    Ideal requirement: 25 cm = 0.25 meters per radio

    Waste: 2% of wire is wasted, so only 98% is usable

    Therefore, to get 0.25 m of usable wire, we must purchase more than that

    ? Adjusted Wire Requirement per Unit:
    Required wire to buy
    =
    0.25
    0.98
    =
    0.2551
     meters (rounded to 4 dp)
    Required wire to buy=
    0.98
    0.25
    ?
    =0.2551 meters (rounded to 4 dp)
    ? Material Cost per Unit:
    0.2551
    ×
    0.50
    =
    $
    0.1276
    ?
    $
    0.13
    0.2551×0.50=$0.1276?
    $0.13
    ?
    2. Labour Cost per Hour (Including Idle Time)
    Time to assemble = 30 minutes = 0.5 hours per radio

    Hourly wage = $12.60

    Idle time = 10% ? Only 90% of hours are productive

    ? Effective Productive Hours:
    To get 0.5 productive hours, we need to pay for more time.

    Paid hours
    =
    0.5
    0.9
    =
    0.5556
     hours (rounded to 4 dp)
    Paid hours=
    0.9
    0.5
    ?
    =0.5556 hours (rounded to 4 dp)
    ? Labour Cost per Unit:
    0.5556
    ×
    12.60
    =
    $
    7.0006
    ?
    $
    7.00
    0.5556×12.60=$7.0006?
    $7.00
    ?
    2. Labour Cost per Hour (Including Idle Time)
    Time to assemble = 30 minutes = 0.5 hours per radio

    Hourly wage = $12.60

    Idle time = 10% ? Only 90% of hours are productive

    ? Effective Productive Hours:
    To get 0.5 productive hours, we need to pay for more time.

    Paid hours
    =
    0.5
    0.9
    =
    0.5556
     hours (rounded to 4 dp)
    Paid hours=
    0.9
    0.5
    ?
    =0.5556 hours (rounded to 4 dp)
    ? Labour Cost per Unit:
    0.5556
    ×
    12.60
    =
    $
    7.0006
    ?
    $
    7.00
    0.5556×12.60=$7.0006?
    $7.00
    ?

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