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Relevant costing

Forums › Ask ACCA Tutor Forums › Ask the Tutor ACCA PM Exams › Relevant costing

  • This topic has 7 replies, 3 voices, and was last updated 9 years ago by John Moffat.
Viewing 8 posts - 1 through 8 (of 8 total)
  • Author
    Posts
  • September 3, 2016 at 11:04 am #337262
    mika84
    Member
    • Topics: 99
    • Replies: 149
    • ☆☆☆

    Sir, could you please help with the following example:
    H has inventory 15000 kg of M raw material bought 3$/kg for product line discontinued. M has no use but could be sold as scrap for $1 per kg.
    One of company’s current products HN requires 4 kg of raw material available for $5/kg. M can be modified at cost of $0. 75/kg to be used as a substitute for this material. But after modification 5 kg of M is required for every unit of HN.
    What is relevant cost per kg of M to be included in the cost estimate for the tender?

    Calculation of M used for HN gives $3, 25 /kg and this is right answer.
    But why not $4 since it is higher? (selling as scrap)

    September 3, 2016 at 2:52 pm #337305
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54829
    • ☆☆☆☆☆

    Where have you got $4 from? You have typed that M could be sold for scrap for $1 (not $4).

    September 3, 2016 at 3:06 pm #337310
    mika84
    Member
    • Topics: 99
    • Replies: 149
    • ☆☆☆

    I concentrated my attention on 4 kg, and multiplied $1 by 4. Sorry. Really silly mistake…

    September 3, 2016 at 3:26 pm #337321
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54829
    • ☆☆☆☆☆

    No problem 🙂

    September 4, 2016 at 1:05 am #337398
    Samit
    Member
    • Topics: 6
    • Replies: 19
    • ☆

    Sir, can you please explain why the relevant cost per kg of M is $3.25?

    Thanks

    September 4, 2016 at 7:34 am #337427
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54829
    • ☆☆☆☆☆

    Currently the material needed for HN is 4 kg x $5 = $20.

    If they use M instead then they need 5 kg and would pay $0.75 per kg, so a cost of $3.75.

    Therefore by using M they would save $20 – $3.75 = $16.25.

    This is the saving for every 5 kg of M, so the saving per kg = 16.25 / 5 = $3.25 per kg.

    September 4, 2016 at 1:56 pm #337504
    Samit
    Member
    • Topics: 6
    • Replies: 19
    • ☆

    Thanks Sir.

    September 4, 2016 at 2:55 pm #337513
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54829
    • ☆☆☆☆☆

    You are welcome 🙂

  • Author
    Posts
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