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Property, plant & equipment IAS 16

ANAnuja Nair9y ago
Qn) The liverpool company acquired a drilling machine on 1 october 20X5 at a cost of $25 000 and depreciated it at 25% per annum on a straight line basis. On 1 october 20X7, $5000 was spent on an upgrade to the machine in order to improve its efficiency and increase the inflow of economic benefits over the machine's remaining life . According to IAS 16, what depreciation expense should be recognised in profit or loss for the year ended 30 September 20X8 ? My answer: Depreciation from 1 october 20X5 to 30 September 20X7 = (25000 x 25% ) x 2 = 12500 Carrying value at 30 september 20X7 = 25000 - 12500 = 12500 Capitalize $5000 Therefore, depreciation from 30 September 20X7 to 30 September 20X8 = (12500+5000) x 25% = 4375 But the answer key states that the answer is 8750. Where did i go wrong sir ?
MikeLittleMikeLittleTutor9y ago#1
When you have capitalised the additional $5,000, how many more years has this machine got to live? The depreciation on the original $25,000 is still $6,250 and the depreciation on the additional $5,000 is $2,500 giving a total of $8,750 OK?
ANAnuja Nair9y ago#2
But the useful life of the drilling machine isn't stated in the question. So how do you know that the depreciation on the additional $5000 is $2500. $2500 represents 2 years of depreciation. Could you explain sir ?
MikeLittleMikeLittleTutor9y ago#3
What's the useful life if you're given this information? "and depreciated it at 25% per annum on a straight line basis." The drilling machine was already 2 years old when we spent that additional $5,000 so there's only 2 more years of life left OK?
ANAnuja Nair9y ago#4
The useful life is 4 years, i get it now sir. Thank you.
MikeLittleMikeLittleTutor9y ago#5
You're welcome
ANAnuja Nair9y ago#6
Can i just take ($12500 +$5000) x 1/2 years = $8750 ?
MikeLittleMikeLittleTutor9y ago#7
Yes - that's exactly the same as 1/4 x $25,000 + 1/2 x $5,000 But if you want to take 1/2 x ($12,500 + $5,000) that's no problem
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