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Linear Programming

Forums › Ask ACCA Tutor Forums › Ask the Tutor ACCA PM Exams › Linear Programming

  • This topic has 7 replies, 3 voices, and was last updated 9 years ago by John Moffat.
Viewing 8 posts - 1 through 8 (of 8 total)
  • Author
    Posts
  • February 4, 2015 at 10:41 pm #225287
    jefzen2610
    Member
    • Topics: 12
    • Replies: 29
    • ☆

    Hi Sir

    I would like to check if my answer to this question is correct.

    A company produces two products, Product F and G, using the same resources. The company is determining the production plan for this month where there are resources constraints. It has been established, using a linear programming model and graphical means, that at the point where contribution is maximised, there are two resources used by the company that are binding constraints.

    The binding constraints are represented by the following.

    Material C: 2F + 3G < 10800
    Labour 3F + 2G < 10000

    Where F and G represent the units of each product that can be produced

    The number of units of product F would be produced under the optimal production plan is:
    _____________________ units

    The correct answer is 201200

    This is my answer but I won’t be able to show the graph

    Material: 3F + 3G = 10,800 [ F=0; G=3600]
    G=0; F=5400

    Labour; 3F+2G = 10000 [F=0; G=5000]
    G=0; F=3333

    Maximum contribution at point where material line crosses labour line

    Mat: 2F + 3G = 10800 (1)
    Lab: 3F+2G = 10000 (2)

    (1) x 1.5 3F + 4.5G = 16200 (3)
    (3) – (1) 0 + 2.5G = 5400
    G = 2160

    (1) 2F + 6480 = 10800
    2F = 4320
    F = 2160

    Now, I would like to know how the number of units of product F became 201200 produced under the optimal plan?

    February 5, 2015 at 8:36 am #225304
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54659
    • ☆☆☆☆☆

    There is no need to draw a graph. The only purpose of drawing the graph is to find where the maximum is, but there the question tells you where it is!!!!

    Your workings are wrong. You have written: (3) – (1), but it should be (3) – (2)

    Also, the correct answer cannot possibly be 201200. That should be obvious to you anyway just from the equations.

    April 7, 2016 at 2:40 pm #309239
    rhook1
    Member
    • Topics: 0
    • Replies: 3
    • ☆

    Hello sorry to be a pain but I am really stuck on the question above. I have the same one in my revision notes. Could i possibly have a bit more of an explanation?

    I know the answer is 1680 but i am really struggling to get to it, and i have an exam on Saturday.

    April 7, 2016 at 2:51 pm #309245
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54659
    • ☆☆☆☆☆

    Have you watched our free lectures on linear programming, because solving the equations is explained in detail there.

    If you multiply the first equation by 1.5, you get:
    3F + 4.5G = 16,200
    If you subtract the labour equation from this you get:
    0 + 2.5G = 6,200

    So G = 6,200 / 2.5 = 2,480

    If you substitute this in the labour equation you get:

    3F + 4,960 = 10,000
    So 3F = 5,040
    F = 5,040 / 3 = 1,680

    April 7, 2016 at 3:32 pm #309250
    rhook1
    Member
    • Topics: 0
    • Replies: 3
    • ☆

    No I must admit i haven’t watched the lectures, i have only just stumbled across this site just now and I am very impressed.

    I will watch the lectures to try and get a better understanding of linear programming. To be honest I am struggling with it.

    Just before i do, could you just explain why we would multiply by 1.5,.. and deduct 0.5 from the labour …

    I can’t quite see the link…

    Again thanks a lot for your quick response…

    April 8, 2016 at 8:33 am #309276
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54659
    • ☆☆☆☆☆

    You should have learned how to solve simultaneous equations at school and you can do it whichever way you were taught (it will give the same answer).
    The way I did it is to multiply the equation by 1.5 because we then get the same number of F’s in both equations. So then when we subtract, the F’s disappear and we can calculate the value of F.
    I didn’t subtract 0.5 anywhere.

    April 8, 2016 at 10:16 am #309291
    rhook1
    Member
    • Topics: 0
    • Replies: 3
    • ☆

    Oh my …thanks ever so much, i fully understand now,… spent ages on that one….!!!
    …
    Again,……..thanks again what a great site……. keep up the good work!!!!!! 🙂

    April 8, 2016 at 12:33 pm #309305
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54659
    • ☆☆☆☆☆

    Thank you 🙂

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