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Learning Rate (Log rule)

Forums › Ask ACCA Tutor Forums › Ask the Tutor ACCA PM Exams › Learning Rate (Log rule)

  • This topic has 3 replies, 2 voices, and was last updated 10 years ago by John Moffat.
Viewing 4 posts - 1 through 4 (of 4 total)
  • Author
    Posts
  • May 15, 2015 at 11:21 am #246110
    Vicks
    Participant
    • Topics: 17
    • Replies: 19
    • ☆

    Hi ,

    I need help with the Log rule. Can you help me with the following question :

    A manufacturing company wants to measure the learning rate that it has achieved with the manufacture of a new product item. The first item produced took 6 hours to make and the average time for the first 16 units was 3.3 hours.

    What has been the learning rate for this product, to the nearest 1 % ?

    I understand the doubling rule of 2 to the power of 4 gives you 16.

    So from the first of 6 hours and 16 of 3.3 hours I divide 3.3/6 to give me 0.55.

    so 0.55 equals R to the power of 4.

    From here I get slightly confused … I calculate it as Log2(0.55) which gives me -0.862 so to the nearest 1% i say its 86%.

    Can you advise me of a slightly different method ? or how you would tackle this question?

    Thank you in advance 🙂

    May 15, 2015 at 12:13 pm #246123
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54748
    • ☆☆☆☆☆

    You cannot be asked to calculate the learning rate using the log formula – only using the doubling rule.

    R^4 = 0.55

    So R = fourth root of 0.55 = 0.86 (or 86%)

    (To take a fourth root, either use the relevant buttons on your calculator, or alternatively just take the square root twice)

    May 15, 2015 at 12:25 pm #246129
    Vicks
    Participant
    • Topics: 17
    • Replies: 19
    • ☆

    Thank you 🙂

    May 15, 2015 at 2:58 pm #246147
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54748
    • ☆☆☆☆☆

    You are welcome 🙂

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