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BBenny10y ago
Hi Sir I do have another question as well. A business's bank balance increased by $750,000 during its last financial year. During the same period it issued shares of $1 million and repaid a loan note of $750,000. It purchased non-current assets for $200,000 and charged depreciation of $100,000. Working capital (other than the bank balance) increased by $575,000. What was its profit for the year? A $1,175,000 B $1,275,000 C $1,325,000 D $1,375,000 The ans is A. However my calculation is B. Could you kindly explain as well. Thank You.
John MoffatJohn MoffatTutor10y ago#1
Surely BPP show explanations of their answers? This is a question on Statement of cash flows. Cash inflows = $1M Cash outflows = 750,000 + 200,000 = $950,000 So excluding cash flows for operating activities, there is a net inflow of 50,000. Since cash increased by 750,000, the cash from operating activities = 700,000. Therefore the profit = 700,000 - 100,000 (depreciation) + 575,000 (increase in working capital) = 1175000 I do suggest you watch our free lecture on Statements of cash flows. Our lectures are a complete course covering everything you need to be able to pass Paper F3.
BBenny10y ago#2
Hi Sir Thank you for the explanation. BPP text do have the explanation. However, the part which i do not understand is that the depreciation was being added back. Below is the ans. Profit for the year 1,175 Add back depreciation 100 1,275 Add: issue of shares 1,000 Less: repayment of loan notes (750) Less: purchase of non current assets (200) 1,325 Less: increase in working capital (575) Increase in bank balance 750
John MoffatJohn MoffatTutor10y ago#3
We always add back depreciation to the profit to get the cash flow from operations, because depreciation was an expense in arriving at the profit, but is not a cash flow. (and therefore if know the cash flow from operations, we need to subtract the depreciation in order to get back to the profit.) Again, I do suggest that you watch the free lecture on Statements of cash flows.
BBenny10y ago#4
Ok. Thank you for the explanation.
John MoffatJohn MoffatTutor10y ago#5
You are welcome :-)
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