A company is planning to purchase 90,800 units of a particular item in the year ahead. The item is purchased in boxes each containing 10 units of the item, at a price of $200 per box. A safety inventory of 250 boxes is kept.
The cost of holding an item in inventory for a year (including insurance, interest and space costs) is 15% of the purchase price. The cost of placing and receiving orders is to be estimated from cost data collected relating to similar orders, where costs of $5,910 were incurred on 30 orders. It should be assumed that ordering costs change in proportion to the number of orders placed. 2% should be added to the above ordering costs to allow for inflation. Assume that usage of the item will be even over the year.
Workings:
To avoid confusion this question is best tackled by working in boxes not units.
Co = 5910/30 x 1.02 = 200.94
Ch = 0.15 x 200 = $30 per box
D = 90,800/10 = 9,080 boxes
EOQ = ?(2x200.94) x 9,080/30) = 349 boxes
No. of orders per year = 9,080/349 = 26
26 orders per annum is equivalent to placing an order every 2 weeks (52 weeks / 26 orders).
I have only one question, in Co, how did we get 1.02?
ACCA Forums
MAEOQ
Multiplying by 1.02 is the same as adding 2% (for inflation).
If you prefer, then Co (without inflation) is 5910/30 = $197.
Because of inflation add on 2% x 197 which is $3.94
Which gives Co = 197 + 3.94 = $200.94
Thank you sir for the clarification.
You are welcome :-)
Thanks a lot for your guide. But this solution make more complication on question. You solved in a right way.
The order quantity which minimises total costs is 3,487
This will mean ordering the item every 2 weeks
I have only one question, in Co, how did we get 3,487?
We order in boxes and there are 10 in each box.
Can u plz explain the final answer(3487)by solving it .Iam confused
The working are shown in the very first post (except that the workings there are in boxes, and there are 10 in each box).
I assume that you have watched my free lectures on the calculation of the EQO :-)
This topic is locked — no new replies.
