• Skip to primary navigation
  • Skip to main content
  • Skip to primary sidebar
Free ACCA & CIMA online courses from OpenTuition

Free ACCA & CIMA online courses from OpenTuition

Free Notes, Lectures, Tests and Forums for ACCA and CIMA exams

  • ACCA
  • CIMA
  • FIA
  • OBU
  • Books
  • Forums
  • Ask AI
  • Search
  • Register
  • Login
  • ACCA Forums
  • Ask ACCA Tutor
  • CIMA Forums
  • Ask CIMA Tutor
  • FIA
  • OBU
  • Buy/Sell Books
  • All Forums
  • Latest Topics

20% off ACCA & CIMA Books

OpenTuition recommends the new interactive BPP books for March and June 2025 exams.
Get your discount code >>

Constraints- question 16, B chemicals – Kaplan kit

Forums › Ask ACCA Tutor Forums › Ask the Tutor ACCA PM Exams › Constraints- question 16, B chemicals – Kaplan kit

  • This topic has 9 replies, 5 voices, and was last updated 7 years ago by John Moffat.
Viewing 10 posts - 1 through 10 (of 10 total)
  • Author
    Posts
  • November 8, 2013 at 9:05 am #144929
    Anonymous
    Inactive
    • Topics: 1
    • Replies: 4
    • ☆

    Hi all,

    Below is the answer give in the kit, I do not understand how market/ demand equation is solved , any help is greatly appreciated.

    X- super petrol
    Y- regular petrol
    C-contribution

    Constraints:

    Heavy: .7x + .5y = 5000
    Light: .5x + .7y = 6000
    Market: x>=2/3 (x + y)
    Contribution : .25x + .10y

    I have worked out heavy and light constraints figure, but figure how to work demand to plot it on graph paper.

    Please someone help me!

    November 8, 2013 at 12:31 pm #145004
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54659
    • ☆☆☆☆☆

    If I understand you correctly, the line yo hare trying to plot is x = 2/3(x + y)

    If you multiply both sides by 3, then 3x = 2x + 2y, which simplifies to x = 2y

    Two points fix a line. One point is x=0 and y=0

    For a second point, choose any value of y that will fit on your graph (for example, if y = 100 then x = 200)
    Then plot the line through the points 🙂

    (Since the inequality is x > 2y, then it will be points either on, or to the ‘x’ side of the line (it depends which axis you have let be x)

    November 15, 2013 at 4:45 pm #146191
    jeile
    Member
    • Topics: 2
    • Replies: 21
    • ☆

    I was going mad with that question as well (clearly not a mathematician!).. However, I am trying to draw the objective function here but cannot understand what I need to do…

    November 16, 2013 at 8:45 am #146259
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54659
    • ☆☆☆☆☆

    The angle of the contribution line will be the same, whatever the total contribution turns out to be.

    So you need to draw the line for any level of total contribution that you want (a guess).

    Then, because the angle will be the same whatever the level of contribution, you move it away from the origin as far as you can (without leaving the feasible area) to fine which point gives the maximum contribution.

    If you have not already done so, the n it will be worth watching my lecture here on linear programming, where I explain this in detail.

    November 24, 2015 at 7:35 pm #284974
    hemraj123
    Member
    • Topics: 110
    • Replies: 188
    • ☆☆☆

    Sir, in this question do we ignore the fact that there is a wastage of 0.2 grams?

    November 25, 2015 at 7:45 am #285088
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54659
    • ☆☆☆☆☆

    I do not have the Kaplan Exam Kit, so I cannot answer your question.

    November 25, 2015 at 9:19 am #285126
    hemraj123
    Member
    • Topics: 110
    • Replies: 188
    • ☆☆☆

    Never mind sir, I understood the question now.

    Thank you

    November 25, 2015 at 11:03 am #285147
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54659
    • ☆☆☆☆☆

    You are welcome 🙂

    November 11, 2017 at 6:33 am #415198
    iza1
    Participant
    • Topics: 115
    • Replies: 112
    • ☆☆☆

    Why is the feasible region of x=2y to the downward direction?

    November 11, 2017 at 9:19 am #415218
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54659
    • ☆☆☆☆☆

    It is not x = 2y, it is x > 2y

    I do not know what you mean by ‘the downward direction’. The constraint is that area where x is greater than 2y.

  • Author
    Posts
Viewing 10 posts - 1 through 10 (of 10 total)
  • The topic ‘Constraints- question 16, B chemicals – Kaplan kit’ is closed to new replies.

Primary Sidebar

Donate
If you have benefited from our materials, please donate

ACCA News:

ACCA My Exam Performance for non-variant

Applied Skills exams is available NOW

ACCA Options:  “Read the Mind of the Marker” articles

Subscribe to ACCA’s Student Accountant Direct

ACCA CBE 2025 Exams

How was your exam, and what was the exam result?

BT CBE exam was.. | MA CBE exam was..
FA CBE exam was.. | LW CBE exam was..

Donate

If you have benefited from OpenTuition please donate.

PQ Magazine

Latest Comments

  • Nicholas1239798 on IASB Conceptual Framework – Introduction – ACCA Financial Reporting (FR)
  • Starmoon123 on Strategy formulation (Part 2) – ACCA (AFM) lectures
  • nosiphoceliwedlamini@gmail.com on Revenue – Example 5 (profitable contracts) – ACCA Financial Reporting (FR)
  • amaanalli on Fraud, bribery, whistle-blowing and company ethics – ACCA Strategic Business Leader (SBL)
  • verweijlisa on Group SPL – Group profit on disposal – ACCA Financial Reporting (FR)

Copyright © 2025 · Support · Contact · Advertising · OpenLicense · About · Sitemap · Comments · Log in