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Please I don’t know how to use the Normal Distributor Table e.g if am to find N(d1), where N (d1) means delta, the probability that a deviation of less than d1, will occur in a normal distribution with a mean of zero, standard deviation of 1. Now, N(0.5418) = 5 +.0.2060 according to my revision kit. I understand that when N is greater than ZERO then, 5 will added and a less than 0 mean it will be deducted. How the 0.2060 was arrived at, I don’t know. I checked 0.5 on the row straight to the column 0.04 but 0.2054 was the result.
Please, kindly help.
What you have for (0.2054) is fine for the exam.
What the answer has done is said that because we wanted .5418 (not .54) then they apportioned between the results for .54 and .55. There is no need to do that in the exam.
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