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Bottleneck process

Forums › Ask ACCA Tutor Forums › Ask the Tutor ACCA PM Exams › Bottleneck process

  • This topic has 1 reply, 2 voices, and was last updated 7 years ago by John Moffat.
Viewing 2 posts - 1 through 2 (of 2 total)
  • Author
    Posts
  • December 2, 2017 at 6:07 pm #419777
    sheri12
    Member
    • Topics: 19
    • Replies: 15
    • ☆

    There are three processes 1, 2 and 3 , DAILY HOURS AVIALBLE FOR P1 ARE 22 HOURS, P2 ARE 22 HOURS AND P3 ARE18 HOURS.
    TIME FOR one unit of X IN P1 IS 1 HOURR, P2 IS 0.75 HOUR AND P3 IS1 HOUR
    Time FOR one unit of Y IN P1 IS 0.75 HOUR, P2 IS 1 HOUR AND P3 IS 0.5 HOUR

    Daily demand OF X IS 10 UNITS AND OF Y IS 16 UNITS
    what the bottleneck process?
    kindly help

    December 3, 2017 at 5:45 am #419842
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54664
    • ☆☆☆☆☆

    The time needed in P1 is (10 x 1) + (16 x 0.75) = 22 hours
    The time needed in P2 is (10 x 0.75) + (16 x 1) = 23.5 hours
    The time needed in P3 is (10 x 1) + (16 x 0.5) = 18 hours

    It is only P2 where there are not enough hours available, and so P2 is the bottleneck.

    (Why are you attempting questions for which you do not have an answer? You should be using a Revision Kit from one of the ACCA approved publishers – they are answers and workings!)

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  • The topic ‘Bottleneck process’ is closed to new replies.

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