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- February 3, 2017 at 10:49 pm #370969
sorry for replyng you back, iam still confused. the first equation is in kg ( 2S+4E=80KG ), and second equation in Hours ( 5S+6E=180 Hours ). we are solving this equation by multiplying by 2.5. i understood that part. but first equation is in KG ( 80KG) second equation is in Hours (180)Hours. when we deduct after multiplication it is showing 200 kg-180 hours, and we arrived to the results of 4E = 20. is this correct to deduct 200 from 180 since both are in different category ( KG & Hours )?
January 31, 2017 at 10:07 pm #370443iam having a doubt on Chapter 6 (Limiting Factors ). in the example we have taken the equation as follows
MATERIAL – 2S+4E=80 KG
LABOUR – 5S+6E=180 HOURS
In this case we are trying to solve the equation by multiplying the material by 2.5. how can we solve this equation since the first one in KG and second one in Labour hours. Can we do in this way? iam confused. please explain. iam sorry if i asked you a stupid question. - AuthorPosts