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Active 1 year ago
  • Topics: 2
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Viewing 4 posts - 1 through 4 (of 4 total)
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  • October 19, 2015 at 2:57 am #277233
    ed8385d05ad3f0dba9c5131b84b641512b688de36663df15b58524c56cc4a394 80matov
    Participant
    • Topics: 2
    • Replies: 4
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    Pass!!! 3th attempt but finally PASSED! 😉

    September 4, 2015 at 7:14 pm #269865
    ed8385d05ad3f0dba9c5131b84b641512b688de36663df15b58524c56cc4a394 80matov
    Participant
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    Thank you John,
    Sorry for my misunderstanding. I will watch lectures again.

    Best regards,

    Vladimir

    September 4, 2015 at 5:12 pm #269856
    ed8385d05ad3f0dba9c5131b84b641512b688de36663df15b58524c56cc4a394 80matov
    Participant
    • Topics: 2
    • Replies: 4
    • ☆

    Hello John,
    The Question is exactly the same Higgins.

    I solve the equations:
    1.) 0.270P+0.270S < 5400
    2.) 0.5P+0.75S < 12000
    Multiply 2nd one by 0.54 I derive equation 3.):
    3.) 0.275P+0.275S = 6480
    Then I get the result S=8000 P=12000

    But these results are not profit maximising results.

    In this way I am trying to get the right answer before making graph. But as I sow these method which I use is wrong in terms of contribution maximising.

    In this way I found optimal use of resource but not contribution maximising solution.

    August 31, 2015 at 9:21 pm #269359
    ed8385d05ad3f0dba9c5131b84b641512b688de36663df15b58524c56cc4a394 80matov
    Participant
    • Topics: 2
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    • ☆

    Thank you Mr. Moffat for your expert and soon respond!

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Viewing 4 posts - 1 through 4 (of 4 total)

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