Hi sir! I wonder is there any solution for 3 and more combination of products? S and E can be illustrated on graph and through equation, but how can we figure out optimal production if there 3, 4, etc. products? Thank you!

As I make clear in the lectures we can only deal with 2 products using the graphical method. (There is a method for dealing with more than 2 products which is called simplex, but this is not examinable in Paper PM).

Good day? I would like to ask if this kind of linear programming exam question is less likely to appear in the machine mode, as I don’t think this can be done in the CBE.

Because the line that we draw when it is equals is the boundary. If it is a less than constraint then any values of the two variables must be either on the line (i.e. equals the constraint) or below the line (i.e. less than the constraint).

Thanks Mr John and good morning. It is possible to do the inverse of the x and y axes for standard and executive chairs and still arrive at the same optimal production plan? Here S is positioned on the vertical axis while E on the horizontal axis.

It does not matter which axis you use for each product – the answer will be the same (even though the lines will look different).

However, do appreciate that you cannot be asked in the exam to draw the graph – but what can happen is that the graph might be already drawn for you in the question, and you can be tested that you understand it.

Uspanovd says

Hi sir! I wonder is there any solution for 3 and more combination of products? S and E can be illustrated on graph and through equation, but how can we figure out optimal production if there 3, 4, etc. products?

Thank you!

John Moffat says

As I make clear in the lectures we can only deal with 2 products using the graphical method. (There is a method for dealing with more than 2 products which is called simplex, but this is not examinable in Paper PM).

Yuchenhk says

Good day?

I would like to ask if this kind of linear programming exam question is less likely to appear in the machine mode, as I don’t think this can be done in the CBE.

raaaj says

You can be asked to interpret it. It has been examined in the previous papers given by students and often appears as a section A or B question

Reds1337 says

Good Afternoon,

I am not sure how we got the S=0; E=20 / E=0; S=40 from the Materials =2s+4e=80

John Moffat says

If S = 0, then 0 + 4e = 80, therefore e = 80/4 = 20.

If E = 0, then 2s + 0 = 80, therefore s = 80/2 = 40.

Reds1337 says

Thank you

siginacm56 says

Hello sir

Can I use these lectures and notes for June 2022 exam??

John Moffat says

Yes, of course. Our lectures are always updated for the current syllabus (and the current syllabus does not change until after the June 2022 exam).

Lesego says

thank you for the lecture. well explained

josephjoy says

Dear Sir

Why are we assuming that greater than or lesser than symbol is deemed to be “equals” symbol in finding the coordinates for constraints

John Moffat says

Because the line that we draw when it is equals is the boundary. If it is a less than constraint then any values of the two variables must be either on the line (i.e. equals the constraint) or below the line (i.e. less than the constraint).

I do explain this in the lectures.

alie2018 says

Thanks Mr John and good morning. It is possible to do the inverse of the x and y axes for standard and executive chairs and still arrive at the same optimal production plan? Here S is positioned on the vertical axis while E on the horizontal axis.

John Moffat says

It does not matter which axis you use for each product – the answer will be the same (even though the lines will look different).

However, do appreciate that you cannot be asked in the exam to draw the graph – but what can happen is that the graph might be already drawn for you in the question, and you can be tested that you understand it.

alie2018 says

Okay Sir. Thanks