This lecture is great! Love the algebra and power of graphs
D
Dany·
Hi sir! I wonder is there any solution for 3 and more combination of products? S and E can be illustrated on graph and through equation, but how can we figure out optimal production if there 3, 4, etc. products?
Thank you!
J
John MoffatTutor·
As I make clear in the lectures we can only deal with 2 products using the graphical method. (There is a method for dealing with more than 2 products which is called simplex, but this is not examinable in Paper PM).
Y
Yuchen·
Good day?
I would like to ask if this kind of linear programming exam question is less likely to appear in the machine mode, as I don't think this can be done in the CBE.
R
Raaj·
You can be asked to interpret it. It has been examined in the previous papers given by students and often appears as a section A or B question
E
Erica·
Good Afternoon,
I am not sure how we got the S=0; E=20 / E=0; S=40 from the Materials =2s+4e=80
J
John MoffatTutor·
If S = 0, then 0 + 4e = 80, therefore e = 80/4 = 20.
If E = 0, then 2s + 0 = 80, therefore s = 80/2 = 40.
E
Erica·
Thank you
J
John MoffatTutor·
Yes, of course. Our lectures are always updated for the current syllabus (and the current syllabus does not change until after the June 2022 exam).
L
Lesego·
thank you for the lecture. well explained
J
Joseph·
Dear Sir
Why are we assuming that greater than or lesser than symbol is deemed to be "equals" symbol in finding the coordinates for constraints
J
John MoffatTutor·
Because the line that we draw when it is equals is the boundary. If it is a less than constraint then any values of the two variables must be either on the line (i.e. equals the constraint) or below the line (i.e. less than the constraint).
I do explain this in the lectures.
A
alie2018·
Thanks Mr John and good morning. It is possible to do the inverse of the x and y axes for standard and executive chairs and still arrive at the same optimal production plan? Here S is positioned on the vertical axis while E on the horizontal axis.
J
John MoffatTutor·
It does not matter which axis you use for each product - the answer will be the same (even though the lines will look different).
However, do appreciate that you cannot be asked in the exam to draw the graph - but what can happen is that the graph might be already drawn for you in the question, and you can be tested that you understand it.
Thank you!
I would like to ask if this kind of linear programming exam question is less likely to appear in the machine mode, as I don't think this can be done in the CBE.
I am not sure how we got the S=0; E=20 / E=0; S=40 from the Materials =2s+4e=80
If E = 0, then 2s + 0 = 80, therefore s = 80/2 = 40.
Why are we assuming that greater than or lesser than symbol is deemed to be "equals" symbol in finding the coordinates for constraints
I do explain this in the lectures.
However, do appreciate that you cannot be asked in the exam to draw the graph - but what can happen is that the graph might be already drawn for you in the question, and you can be tested that you understand it.