Limiting Factors – Graphical Approach – ACCA Performance Management (PM)
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Hi sir! I wonder is there any solution for 3 and more combination of products? S and E can be illustrated on graph and through equation, but how can we figure out optimal production if there 3, 4, etc. products?
Thank you!
As I make clear in the lectures we can only deal with 2 products using the graphical method. (There is a method for dealing with more than 2 products which is called simplex, but this is not examinable in Paper PM).
Good day?
I would like to ask if this kind of linear programming exam question is less likely to appear in the machine mode, as I don’t think this can be done in the CBE.
You can be asked to interpret it. It has been examined in the previous papers given by students and often appears as a section A or B question
Good Afternoon,
I am not sure how we got the S=0; E=20 / E=0; S=40 from the Materials =2s+4e=80
If S = 0, then 0 + 4e = 80, therefore e = 80/4 = 20.
If E = 0, then 2s + 0 = 80, therefore s = 80/2 = 40.
Thank you
Hello sir
Can I use these lectures and notes for June 2022 exam??
Yes, of course. Our lectures are always updated for the current syllabus (and the current syllabus does not change until after the June 2022 exam).
thank you for the lecture. well explained
Dear Sir
Why are we assuming that greater than or lesser than symbol is deemed to be “equals” symbol in finding the coordinates for constraints
Because the line that we draw when it is equals is the boundary. If it is a less than constraint then any values of the two variables must be either on the line (i.e. equals the constraint) or below the line (i.e. less than the constraint).
I do explain this in the lectures.
Thanks Mr John and good morning. It is possible to do the inverse of the x and y axes for standard and executive chairs and still arrive at the same optimal production plan? Here S is positioned on the vertical axis while E on the horizontal axis.
It does not matter which axis you use for each product – the answer will be the same (even though the lines will look different).
However, do appreciate that you cannot be asked in the exam to draw the graph – but what can happen is that the graph might be already drawn for you in the question, and you can be tested that you understand it.
Okay Sir. Thanks