I don’t have scientific calculator but as everyone know we can use it on the display at exam. So I tried to use online scientific calculator. However, the right number doesn’t come out. Could you please explain how to calculate 3 route x. In this case 3 (X) 3 route How should I start? 3?(3 × (3 ÷ 4 × 5 × 4000000 ÷ 0.0000014)) = 3?(3 ÷ 4 × 5 × 4000000 ÷ 0.0000014) × 3 = 3 × (3 ÷ 4 × 5 × 4000000 ÷ 0.0000014) × 3?() = Error I tried 3 ways, but non of them made right Thank you for your help in advance.
Sir, thank you very much for your excellent lectures. I just have one question to ask: Nowadays, with the development of Internet banking, the transaction cost is almost nearly 0. In that case, would that make the ‘spread’ become zero? Hope to get your response soon! Best wishes to you ?
I had to the the square root 1st before i Multiplied which would be confusing for anyone who is doing it and I believe based on the formula it should not be that way.
There is no square root involved. The result within the bracket is taken to the power of 1/3 (which is the same as taking the third root) and this result is then multiplied by 3.
Sir i am unable to reach the figure of 14,250 spread, i do exactly what you say 3(3/4*5*(2000)^2/0.00014)1/3 & i am getting the answer something like this 3.689868805×10^33. Yes i am using x3 button on calculator to do 1/3.
Thank you for the well explained and detailed lecture, John. I was worried about this topic when I went through the notes, but I felt it quite easily because of your explanation.
I just wanted to take some time to show my appreciation for all your lectures John. I love the enthusiasm you show in each lecture and I have always finished one of your lectures with a good understanding of that particular topic. I would recommend that everyone watch the full lecture and refer to the study notes as I find some of the questions asked on this comment section have already been thoroughly explained in either or both. I have told everyone I know studying ACCA about open tuition and will continue to be an advocate of this website. Keep up the great work!
Just want to say thank you for the lecture Mr. Moffat. I was finding this a little hard to understand from the study text alone, and your explanation really cleared things up.
Hi, I’m getting really confused trying to work out the formula for the spread. Any time I try doing it in different variances I always come back to 6850. Please can you provide step by step instructions on how to do this? Thanks
The formula has the variance in it, and the variance is the square of the standard deviation. You cannot be tested on the rationale, but if you want to know more about the variance then watch the Paper MA (was Paper F2) lectures on statistics.
Could you please explain how did you work out the answer for Example 3 chapter 6. For the formulae Spread, I did not how did you do to get to to: 14,250? Thank you.
I am a bit puzzled as to which bit of the calculation you are not clear about, because I do go through the workings in the lecture and otherwise it is just calculator work.
(I assume you are clear that taking something to the power of 1/3 is another way of writing that it is the third root of what is in the brackets, and obviously for that bit you need to be using a scientific calculator.)
The calculations needed depend what information is given in the question. If you look at questions on this in your Revision Kit then you will see what I mean.
Maitya says
I don’t have scientific calculator but as everyone know we can use it on the display at exam. So I tried to use online scientific calculator. However, the right number doesn’t come out.
Could you please explain how to calculate 3 route x.
In this case 3 (X) 3 route
How should I start?
3?(3 × (3 ÷ 4 × 5 × 4000000 ÷ 0.0000014)) =
3?(3 ÷ 4 × 5 × 4000000 ÷ 0.0000014) × 3 =
3 × (3 ÷ 4 × 5 × 4000000 ÷ 0.0000014) × 3?() = Error
I tried 3 ways, but non of them made right
Thank you for your help in advance.
Maitya says
the ? is route
didn’t show up right
orcist123 says
Sir, thank you very much for your excellent lectures. I just have one question to ask: Nowadays, with the development of Internet banking, the transaction cost is almost nearly 0. In that case, would that make the ‘spread’ become zero? Hope to get your response soon!
Best wishes to you ?
John Moffat says
In the case of just using a deposit account then yes. However if instead money is invested in securities then there obviously is a transaction cost.
orcist123 says
Thank you for your response, sir :))
mariochase24 says
I am getting 6850 as well and I am pretty guy with calculations so either some figure in the formula is wrong are you calculation i incorrect
mariochase24 says
I had to the the square root 1st before i Multiplied which would be confusing for anyone who is doing it and I believe based on the formula it should not be that way.
John Moffat says
The formula is correct and so is the answer.
There is no square root involved. The result within the bracket is taken to the power of 1/3 (which is the same as taking the third root) and this result is then multiplied by 3.
geniuz999 says
Sir i am unable to reach the figure of 14,250 spread, i do exactly what you say 3(3/4*5*(2000)^2/0.00014)1/3 & i am getting the answer something like this 3.689868805×10^33. Yes i am using x3 button on calculator to do 1/3.
John Moffat says
We are not multiplying by 1/3.
It is to the power 1/3 which is the same as taking the third root.
ayshak16 says
Thank you for the well explained and detailed lecture, John. I was worried about this topic when I went through the notes, but I felt it quite easily because of your explanation.
John Moffat says
Thank you for your comment 🙂
robbomac90 says
I just wanted to take some time to show my appreciation for all your lectures John. I love the enthusiasm you show in each lecture and I have always finished one of your lectures with a good understanding of that particular topic. I would recommend that everyone watch the full lecture and refer to the study notes as I find some of the questions asked on this comment section have already been thoroughly explained in either or both. I have told everyone I know studying ACCA about open tuition and will continue to be an advocate of this website. Keep up the great work!
John Moffat says
Thank you very much for your comment 🙂
danielle.ezra says
Just want to say thank you for the lecture Mr. Moffat. I was finding this a little hard to understand from the study text alone, and your explanation really cleared things up.
John Moffat says
Thank you 🙂
liam142 says
Hi, I’m getting really confused trying to work out the formula for the spread. Any time I try doing it in different variances I always come back to 6850. Please can you provide step by step instructions on how to do this? Thanks
rajeshops says
Mr. John,
First of all, thank you and all your team for the amazing lectures and materials.
Secondly, could you please check the calculation of spread? As per my calc it comes as 6850.
I understand that it is not so important, but…
John Moffat says
The calculation in the lecture is correct – the spread is 14,250.
plightbourne says
I just watched the full lecture so you can DISREGARD my previous comment
vir619 says
(3/4*5*400000/0.00014)^(1/3)
i applied this formula on excel sheet and the result coming out is 2204 instead of 4750.
John Moffat says
2,000^2 = 4,000,000 (not 400,000)
vir619 says
yes.. i didn’t notice that..and may be there is a printing mistake on the note.. 400000 is written there…
John Moffat says
You are correct – thanks. I will have it corrected.
However I think (hope!) that I show the correct figures in the lecture 🙂
plightbourne says
Hello,
I was able to work out the answer based on your comments. Please humor me as this aspect of math has never been my strong point.
I don’t get the rationale behind ‘2,000^2’ for the daily deviation. Explain this to me like you would a ‘5 year old’
John Moffat says
The formula has the variance in it, and the variance is the square of the standard deviation.
You cannot be tested on the rationale, but if you want to know more about the variance then watch the Paper MA (was Paper F2) lectures on statistics.
kimbeckett1 says
Hi Sir
Could you please explain how did you work out the answer for Example 3 chapter 6. For the formulae Spread, I did not how did you do to get to to: 14,250? Thank you.
John Moffat says
I am a bit puzzled as to which bit of the calculation you are not clear about, because I do go through the workings in the lecture and otherwise it is just calculator work.
(I assume you are clear that taking something to the power of 1/3 is another way of writing that it is the third root of what is in the brackets, and obviously for that bit you need to be using a scientific calculator.)
kimbeckett1 says
Thank you Sir, I got it.
John Moffat says
Great 🙂
dheel says
Sir, why did you use the daily interest rate in the formula?
Samuel Koroma says
The calculations are as follows:
(a) upper limit
(b) lower limit
(c) spread
(d) return point
The spread is needed to calculate the return point and the upper limit
John Moffat says
I don’t really know why you have written this 🙂
The calculations needed depend what information is given in the question. If you look at questions on this in your Revision Kit then you will see what I mean.
Samuel Koroma says
Okay sir noted. I did that just to recall what I learnt from your presentation.
John Moffat says
OK 🙂