- This topic has 1 reply, 2 voices, and was last updated 1 year ago by
.
Viewing 2 posts - 1 through 2 (of 2 total)
- Posts
The returns from a project are normally distributed with a mean of $200,000 and a standard deviation of $160,000.
If the project loses more than $100,000 the company will be in financial difficulties.
What is the probability of the project losing more than $100,000?
Answer is 3%
z=(200000-100000)/160000
z=0.625
In standard normal distribution table value of 0.62=0.2324
0.5 -0.23=0.27 0r 27%Can you tell me where I went wrong?
Viewing 2 posts - 1 through 2 (of 2 total)
- You must be logged in to reply to this topic.