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Chapter 4 – example 6 (b)

Forums › ACCA Forums › ACCA MA Management Accounting Forums › Chapter 4 – example 6 (b)

  • This topic has 4 replies, 2 voices, and was last updated 13 years ago by John Moffat.
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  • March 26, 2012 at 6:47 am #51941
    yan03ky
    Member
    • Topics: 9
    • Replies: 6
    • ☆

    queation is : Descibe the relationship between the output & costs in the form of a linear equation. what is mean? please help!!!

    March 26, 2012 at 9:57 am #95728
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54684
    • ☆☆☆☆☆

    A linear equation is one that graphs as a straight line and is always of the form:
    y = a + bx (where a and b are constants).

    For the relationship between costs and output, y will be the cost and x will be the output in units.

    So, if the equation was (for example) y = 20 + 3x then for any value of x (output) you could calculate the cost (y).

    The object of the exercise is to calculate what the values of a and b are.

    March 26, 2012 at 2:52 pm #95729
    yan03ky
    Member
    • Topics: 9
    • Replies: 6
    • ☆

    Thank you.

    March 26, 2012 at 2:56 pm #95730
    yan03ky
    Member
    • Topics: 9
    • Replies: 6
    • ☆

    another question is chapter 4 – question 5, ask about graphs, I have no idea that how to answer and also don’t understand. Please kindly help why the answer is B!!!

    March 27, 2012 at 5:59 am #95731
    John Moffat
    Keymaster
    • Topics: 57
    • Replies: 54684
    • ☆☆☆☆☆

    Because the variable cost per unit is constant, the graph is linear.

    The line suddenly drops because a lower price per unit applies.

    The new line must go through the origin because the lower price applies retrospectively.

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