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Learning curve question – Kaplan revision kit Q34 Page 12

Forums › Ask CIMA Tutor Forums › Ask CIMA P2 Tutor Forums › Learning curve question – Kaplan revision kit Q34 Page 12

  • This topic has 1 reply, 2 voices, and was last updated 8 years ago by Cath.
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  • Author
    Posts
  • February 12, 2017 at 8:08 am #372053
    francesca09
    Member
    • Topics: 8
    • Replies: 4
    • ☆

    I have encountered the below question and i am not able to get the correct answer with the method i have used. i will be really grateful if i could receive assistance on this regard.

    QUESTION
    A company is developing a new product first makes a prototype for testing, secondly makes a demonstration model, and then begins production. The time taken to make the prototype is 300 hours and from past experience of similar models, it is known that 90% learning curve applies.
    The average time for the first two models is in (hrs):………

    ANSWER is 216

    I’ve tried to solve the above by applying the below formula:
    Y=ax^b

    Y=time in hrs
    a=no of hours incurred for the first unit
    x=no of units
    b=90% learning curve

    Therefore,

    Y=300×2^(-0.1520) = 270

    February 16, 2017 at 1:30 am #372627
    Cath
    Participant
    • Topics: 0
    • Replies: 447
    • ☆☆☆

    Hi, thanks for your question. I can see your thinking and the question wording is a certainly a bit vague.

    However, Im assuming based on the answer of 216 that its actually asking for the average time per model for units 3 and 4 – i.e. the first two models which are made after the prototype and demo are completed.

    i.e.
    first unit takes 300 hours – this is prototype…
    then 90% of this figure the no2 ‘demo model takes cumulative avg time per unit to 270 hours.
    This gives us a total time for first two items of 540 hrs ( 2 x 270).

    Then as the output jumps to 4 units ( i.e. because we go from 1 to 2 to 4 etc).. we will be reducing our cumulative average time per unit to 243 hours each by the fourth item.
    Total time for ALL four items will be 243 x 4 = 972 hours

    Difference between total for four units and total time for first two units will be 432 hours (972h less 540h) … meaning that units 3 and 4 alone took an average of 432/2 = 216hours each.

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