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MA1 Question

Forums › FIA Forums › MA1 Question

  • This topic has 2 replies, 3 voices, and was last updated 10 years ago by Ken Garrett.
Viewing 3 posts - 1 through 3 (of 3 total)
  • Author
    Posts
  • November 21, 2015 at 6:32 am #284262
    pororo
    Member
    • Topics: 8
    • Replies: 12
    • ☆

    2,000 litres of a chemical were manufactured in a period. There is a process loss of 18% (11% because of poor quality material and 7% bacause of bad handling) of the material input in the manufacturing process.

    How many litres of material (to the nearest litre)were input during the period?

    A 1,640
    B 2,247
    C 2,360
    D 2,439

    November 23, 2015 at 4:15 am #284654
    andrewpersaud
    Participant
    • Topics: 4
    • Replies: 6
    • ☆

    Answer is D
    2000/82%= 2439

    November 23, 2015 at 10:08 am #284696
    Ken Garrett
    Keymaster
    • Topics: 10
    • Replies: 10649
    • ☆☆☆☆☆

    If you have trouble getting the right proportions to use, base your input on 100. So:

    Input – Lost = Output
    100 – 18 = 82

    The question gives you

    Input – Lost = Output
    ? – ? = 2,000

    So just use the model proportions (82:100) to move from output to input.

    Input = 2000 x 100/82 = 2,439

    You can check: If 2,439 is input, 18% is lost = 439, so 2,000 is good output.

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