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- This topic has 7 replies, 3 voices, and was last updated 8 years ago by John Moffat.
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- February 4, 2015 at 10:41 pm #225287
Hi Sir
I would like to check if my answer to this question is correct.
A company produces two products, Product F and G, using the same resources. The company is determining the production plan for this month where there are resources constraints. It has been established, using a linear programming model and graphical means, that at the point where contribution is maximised, there are two resources used by the company that are binding constraints.
The binding constraints are represented by the following.
Material C: 2F + 3G < 10800
Labour 3F + 2G < 10000Where F and G represent the units of each product that can be produced
The number of units of product F would be produced under the optimal production plan is:
_____________________ unitsThe correct answer is 201200
This is my answer but I won’t be able to show the graph
Material: 3F + 3G = 10,800 [ F=0; G=3600]
G=0; F=5400Labour; 3F+2G = 10000 [F=0; G=5000]
G=0; F=3333Maximum contribution at point where material line crosses labour line
Mat: 2F + 3G = 10800 (1)
Lab: 3F+2G = 10000 (2)(1) x 1.5 3F + 4.5G = 16200 (3)
(3) – (1) 0 + 2.5G = 5400
G = 2160(1) 2F + 6480 = 10800
2F = 4320
F = 2160Now, I would like to know how the number of units of product F became 201200 produced under the optimal plan?
February 5, 2015 at 8:36 am #225304There is no need to draw a graph. The only purpose of drawing the graph is to find where the maximum is, but there the question tells you where it is!!!!
Your workings are wrong. You have written: (3) – (1), but it should be (3) – (2)
Also, the correct answer cannot possibly be 201200. That should be obvious to you anyway just from the equations.
April 7, 2016 at 2:40 pm #309239Hello sorry to be a pain but I am really stuck on the question above. I have the same one in my revision notes. Could i possibly have a bit more of an explanation?
I know the answer is 1680 but i am really struggling to get to it, and i have an exam on Saturday.
April 7, 2016 at 2:51 pm #309245Have you watched our free lectures on linear programming, because solving the equations is explained in detail there.
If you multiply the first equation by 1.5, you get:
3F + 4.5G = 16,200
If you subtract the labour equation from this you get:
0 + 2.5G = 6,200So G = 6,200 / 2.5 = 2,480
If you substitute this in the labour equation you get:
3F + 4,960 = 10,000
So 3F = 5,040
F = 5,040 / 3 = 1,680April 7, 2016 at 3:32 pm #309250No I must admit i haven’t watched the lectures, i have only just stumbled across this site just now and I am very impressed.
I will watch the lectures to try and get a better understanding of linear programming. To be honest I am struggling with it.
Just before i do, could you just explain why we would multiply by 1.5,.. and deduct 0.5 from the labour …
I can’t quite see the link…
Again thanks a lot for your quick response…
April 8, 2016 at 8:33 am #309276You should have learned how to solve simultaneous equations at school and you can do it whichever way you were taught (it will give the same answer).
The way I did it is to multiply the equation by 1.5 because we then get the same number of F’s in both equations. So then when we subtract, the F’s disappear and we can calculate the value of F.
I didn’t subtract 0.5 anywhere.April 8, 2016 at 10:16 am #309291Oh my …thanks ever so much, i fully understand now,… spent ages on that one….!!!
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Again,……..thanks again what a great site……. keep up the good work!!!!!! 🙂April 8, 2016 at 12:33 pm #309305Thank you 🙂
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