- This topic has 1 reply, 2 voices, and was last updated 10 years ago by
.
- Posts
First of all THANKS is advance John for the great work you are doing here.
I am struggling here with deltas N(d1) and N(d2) in the question Marengo. According to the normal calculations we calculate d1 according to the formula and look up the corresponding figures using the tables. If d1 is greater than 0, we add 0.5 and vice versa.
The problem is I can’t figure out what the examiner has done here…
N(d1)=0.5+0.2291+0.7x (0.234 – 0.2291) = 0.7134
N(d2)=0.5+0.0753+0.3x (0.0793 – 0.0753) = 0.5765
This procedure has been done in a number of other questions as well but I can’t figure it. Maybe its something to do with the tables as I am only looking up to two decimal places i.e instead of 0.617 only looking up 0.61.
Plus I would appreciate if you can reccommend me some readings for deltas and delta hedges as I can’t find something in detail in bpp or kaplan.
All he has done is approximated between the results from the tables.
I don’t think that the figures you have quoted come from Marengo!
Using Marengo however as an example, we want to look up 0.055 in the tables. However we can only look up 0.05 and 0.06, so what he has done is taken the figure for 0.05 (0.0199) and then added 0.5 of the difference between 0.05 and 0.06 from the tables (0.0199 and 0.0239). In that way he has approximated to 0.055.
With regard to deltas and delta hedges, I am surprised if BPP and Kaplan have no detail. Have you read our Course Notes (and watched the free lecture that goes with them)?
- You must be logged in to reply to this topic.