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TR = TC (aq – bq2 = FC + vc/unit x no of units) is this equation examinable

Forums › Ask ACCA Tutor Forums › Ask the Tutor ACCA PM Exams › TR = TC (aq – bq2 = FC + vc/unit x no of units) is this equation examinable

  • This topic has 4 replies, 2 voices, and was last updated 2 years ago by IAW3005.
Viewing 5 posts - 1 through 5 (of 5 total)
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  • May 6, 2023 at 7:58 pm #683998
    hummed
    Participant
    • Topics: 7
    • Replies: 4
    • ☆

    is this equation examinable in the exam? this relates to pricing chapter

    May 6, 2023 at 10:35 pm #684000
    IAW3005
    Moderator
    • Topics: 4
    • Replies: 1604
    • ☆☆☆☆☆

    You can be asked to

    Derive and manipulate a straight line demand equation. Derive an equation for the total cost function(including volume-based discounts).

    The straight line demand equation shows the relationship between price and demand.

    Formula: Demand equation (P) = a – bQ

    P = selling price
    Q = Quantity demanded at that price
    a = a theoretical maximum price at which there is no demand
    b = the change in price required to change demand by 1 unit (gradient)
    To calculate a:

    Formula: a = $(current price) + [ (current quantity at current price ÷ change in quantity when price is changed by $b) x $b]

    To calculate b:

    Formula: b = change in price ÷ change in quantity

    May 6, 2023 at 11:05 pm #684001
    IAW3005
    Moderator
    • Topics: 4
    • Replies: 1604
    • ☆☆☆☆☆

    For example

    Our product is priced at $13. At this price, we sell 75 a month. When we raised the price to $15 we sold 50. Determine the demand equation.

    P = a – bQ
    a = $13 + [(75/25) x $2 = $19
    b = (15 – 12) ÷ (75 – 50) = 0.12

    * Therefore P = 19 – 0.12Q
    * 12 = 19 – 0.12 Q
    * 12-19 = – 0.12 Q
    * Q = 58.33

    May 7, 2023 at 1:30 am #684003
    hummed
    Participant
    • Topics: 7
    • Replies: 4
    • ☆

    This was helpful, Thanks for answering my question

    May 7, 2023 at 11:01 pm #684031
    IAW3005
    Moderator
    • Topics: 4
    • Replies: 1604
    • ☆☆☆☆☆

    Your welcome

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